{"id":18128,"date":"2024-04-25T10:26:27","date_gmt":"2024-04-25T10:26:27","guid":{"rendered":"https:\/\/soicau5006.minhngocxoso.com\/?p=18128"},"modified":"2024-04-25T10:26:27","modified_gmt":"2024-04-25T10:26:27","slug":"mot-so-phuong-phap-choi-dan-dac-biet-de-kha-nang-co-lai-cao","status":"publish","type":"post","link":"https:\/\/kqxs8.com\/mot-so-phuong-phap-choi-dan-dac-biet-de-kha-nang-co-lai-cao\/","title":{"rendered":"m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u00f3 l\u00e3i cao"},"content":{"rendered":"
<\/p>\n\n\n
B\u00e0i vi\u1ebft h\u00f4m nay website c\u1ee7a ch\u00fang t\u00f4i xin g\u1eedi \u0111\u1ebfn c\u00e1c b\u1ea1n m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh d\u00e0n \u0111\u1eb7c bi\u1ec7t \u2013 d\u00e0n \u0111\u1ec1 x\u1ed5 s\u1ed1 3 mi\u1ec1n \u0111\u1ec3 c\u00f3 l\u00e3i v\u00e0 gi\u1ea3m thi\u1ec3u x\u00e1c su\u1ea5t tr\u01b0\u1ee3t nh\u1ea5t.<\/p>\n\n\n\n
D\u00e0n \u0111\u1eb7c bi\u1ec7t ngh\u0129a l\u00e0 ch\u01a1i nhi\u1ec1u s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u1ea1o th\u00e0nh d\u00e0n nh\u01b0 : d\u00e0n \u0111\u1eb7c bi\u1ec7t 19 s\u1ed1, 36 s\u1ed1, 51 s\u1ed1, 64 s\u1ed1.<\/p>\n\n\n\n
\u0110\u1ec3 ch\u01a1i \u0111\u01b0\u1ee3c theo c\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 l\u00e3i th\u00ec y\u1ebfu t\u1ed1 t\u1ec9 l\u1ec7 \u0103n r\u1ea5t quan tr\u1ecdng.B\u00ecnh th\u01b0\u1eddng ch\u00fang ta ghi b\u00ean ngo\u00e0i s\u1ebd \u0103n t\u1ec9 l\u1ec7 1 \u0103n 70, n\u01a1i n\u00e0o cao th\u00ec 1 \u0103n 80 ho\u1eb7c h\u01a1n 80 t\u00ed.Nh\u01b0ng khi ch\u00fang ta ch\u01a1i online t\u1ea1i website c\u1ee7a ch\u00fang t\u00f4i th\u00ec t\u1ec9 l\u1ec7 \u0103n s\u1ebd cao h\u01a1n r\u1ea5t nhi\u1ec1u so v\u1edbi b\u00ean ngo\u00e0i.T\u1ec9 l\u1ec7 \u0103n l\u00f4 \u0111\u1ec1 t\u1ea1i website c\u1ee7a ch\u00fang t\u00f4i \u0111\u1ec1u l\u00e0 1 \u0103n 99.<\/p>\n\n\n\n
Ngh\u0129a l\u00e0 ch\u00fang ta gi 1 ngh\u00ecn \u0111\u1ec1 n\u1ebfu tr\u00fang \u0111\u01b0\u1ee3c 99 ngh\u00ecn, 1 \u0111i\u1ec3m l\u00f4 = 27 ngh\u00ecn n\u1ebfu tr\u00fang \u0111\u01b0\u1ee3c 99 ngh\u00ecn.<\/p>\n\n\n\n
Sau \u0111\u00e2y, website c\u1ee7a ch\u00fang t\u00f4i s\u1ebd chia s\u1ebb m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1ec1 \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u00f3 l\u00e3i cao h\u01a1n.<\/p>\n\n\n\n
V\u1edbi ph\u01b0\u01a1ng ph\u00e1p d\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u01a1i trong ng\u00e0y n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i c\u00e1c d\u00e0n 36 s\u1ed1, 51 s\u1ed1 ho\u1eb7c 64 s\u1ed1.<\/p>\n\n\n\n
D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 1 ch\u1ea1m ( 1 \u0111\u1ea7u v\u00e0 1 \u0111u\u00f4i ), 1 \u0111\u1ea7u 1 \u0111u\u00f4i l\u00e0 20 s\u1ed1 nh\u01b0ng c\u00f3 1 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 19 con.V\u00ed d\u1ee5 ch\u1ea1m 1 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1 v\u00e0 \u0111u\u00f4i 1 d\u00e0n n\u00e0y c\u00f3 1 s\u1ed1 tr\u00f9ng l\u00e0 11.<\/p>\n\n\n\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n\n\n\n
L\u00e3i n\u1ebfu tr\u00fang : 63 ngh\u00ecn<\/p>\n\n\n\n
D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 2 ch\u1ea1m ( 2 \u0111\u1ea7u v\u00e0 2 \u0111u\u00f4i ), 2 \u0111\u1ea7u 2 \u0111u\u00f4i l\u00e0 40 s\u1ed1 nh\u01b0ng c\u00f3 4 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 36 con.V\u00ed d\u1ee5 ch\u1ea1m 1,2 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2 v\u00e0 \u0111u\u00f4i 1,2, d\u00e0n n\u00e0y c\u00f3 4 s\u1ed1 tr\u00f9ng l\u00e0 11,22,12,21.<\/p>\n\n\n\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n\n\n\n
L\u00e3i n\u1ebfu tr\u00fang : 63 ngh\u00ecn<\/p>\n\n\n\n
D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 3 ch\u1ea1m g\u1ed3m 3 \u0111\u1ea7u v\u00e0 3 \u0111u\u00f4i l\u00e0 60 s\u1ed1 nh\u01b0ng c\u00f3 9 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 51 s\u1ed1.V\u00ed d\u1ee5 ch\u1ea1m 1,2,3 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2,3 v\u00e0 \u0111u\u00f4i 1,2,3, d\u00e0n n\u00e0y c\u00f3 9 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n l\u00e0 11,22,33,12,21,13,31,23,32.<\/p>\n\n\n\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n\n\n\n
L\u00e3i n\u1ebfu tr\u00fang : 48 ngh\u00ecn<\/p>\n\n\n\n
D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 4 ch\u1ea1m g\u1ed3m 4 \u0111\u1ea7u v\u00e0 4 \u0111u\u00f4i l\u00e0 80 s\u1ed1 nh\u01b0ng c\u00f3 16 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 64 s\u1ed1.V\u00ed d\u1ee5 ch\u1ea1m 1,2,3,4 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2,3,4 v\u00e0 \u0111u\u00f4i 1,2,3,4,d\u00e0n n\u00e0y c\u00f3 16 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n l\u00e0 11,22,33,44,12,21,13,31,14,41,23,32,24,42,34,43.<\/p>\n\n\n\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n\n\n\n
L\u00e3i n\u1ebfu tr\u00fang : 35 ngh\u00ecn<\/p>\n\n\n\n
V\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1c d\u00e0n 36 s\u1ed1, 51 s\u1ed1.<\/p>\n\n\n\n
+ V\u1edbi d\u00e0n 36 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:2.V\u00ed d\u1ee5 :<\/p>\n\n\n\n
Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 2 ngh\u00ecn.T\u1ed5ng v\u1ed1n l\u00e0 36 + 72 = 108 ngh\u00ecn.<\/p>\n\n\n\n
N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 63 ngh\u00ecn.<\/p>\n\n\n\n
N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 2*99 \u2013 108 = 90 ngh\u00ecn.<\/p>\n\n\n\n
+ V\u1edbi d\u00e0n 51 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:3.V\u00ed d\u1ee5 :<\/p>\n\n\n\n
Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 3 ngh\u00ecn.T\u1ed5ng v\u1ed1n l\u00e0 51 + 153 = 204 ngh\u00ecn<\/p>\n\n\n\n
N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 48 ngh\u00ecn.<\/p>\n\n\n\n
N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 3*99 \u2013 204 = 93 ngh\u00ecn.<\/p>\n\n\n\n